What is (-3x^2+10)-(-2x^2+2) ?

The solution to (-3x^2+10)-(-2x^2+2) is -x^2+8

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simplify (-3x^2+10)-(-2x^2+2)

simplify

(- 3 x^{2} + 10) - (- 2 x^{2} + 2)

- x^{2} + 8

Solution steps

(- 3 x^{2} + 10) - (- 2 x^{2} + 2)

Apply rule:

(a) = a

(- 3 x^{2} + 10) = - 3 x^{2} + 10

= - 3 x^{2} + 10 - (- 2 x^{2} + 2)

Apply the distributive law:

- (- a + b) = a - b

- (- 2 x^{2} + 2) = 2 x^{2} - 2

= - 3 x^{2} + 10 + 2 x^{2} - 2

Group like terms

= - 3 x^{2} + 2 x^{2} + 10 - 2

Add similar elements:

- 3 x^{2} + 2 x^{2} = - x^{2}

= - x^{2} + 10 - 2

Subtract the numbers:

10 - 2 = 8

= - x^{2} + 8

\frac{- 6}{1}

\frac{i}{2} - \frac{i}{5} - i

12 - 3 n

lo g_{1.25} (0.64)

9 b^{3} + 36 b^{2} - 4 b - 16