What is (x^3+8)/(x^2-4) ?

The solution to (x^3+8)/(x^2-4) is (x^2-2x+4)/(x-2)

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simplify (x^3+8)/(x^2-4)

simplify

\frac{x ^{3} + 8}{x ^{2} - 4}

\frac{x ^{2} - 2 x + 4}{x - 2}

Solution steps

\frac{x ^{3} + 8}{x ^{2} - 4}

Factor

x^{3} + 8 : (x + 2) (x^{2} - 2 x + 4)

= \frac{( x + 2 ) ( x ^{2} - 2 x + 4 )}{x ^{2} - 4}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x ^{2} - 2 x + 4 )}{( x + 2 ) ( x - 2 )}

Cancel the common factor:

x + 2

= \frac{x ^{2} - 2 x + 4}{x - 2}

8 + 6 x^{4}

(- 10 c^{4}) (- 3 c^{4})

\frac{8 w}{12 w ^{2}}

ln (e^{x^{2}})

p^{2} + 2 pq + q^{2}