What are the solutions to the equation x^2-2x+50=0 ?

The solutions to the equation x^2-2x+50=0 are x=1+7i,x=1-7i

Find the zeros of x^2-2x+50=0

The zeros of x^2-2x+50=0 are x=1+7i,x=1-7i

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x^{2} - 2 x + 50 = 0

x = 1 + 7 i, x = 1 - 7 i

Solution steps

x^{2} - 2 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 50 : 14 i

x_{1, 2} = \frac{- ( - 2 ) \pm 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 14 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 14 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 14 i}{2 \cdot 1} : 1 + 7 i

x = \frac{- ( - 2 ) - 14 i}{2 \cdot 1} : 1 - 7 i

The solutions to the quadratic equation are:

x = 1 + 7 i, x = 1 - 7 i

\frac{x}{5} + 3 = 9

x^{- \frac{9}{8}}

- 3.8 g + 5 + 2.7 g = 12.7

∣ x ∣ < 4

2 x + 1 \leq 5 x + 7

What are the solutions to the equation x^2-2x+50=0 ?
The solutions to the equation x^2-2x+50=0 are x=1+7i,x=1-7i
Find the zeros of x^2-2x+50=0
The zeros of x^2-2x+50=0 are x=1+7i,x=1-7i