What is (3-5i)/(8+2i) ?

The solution to (3-5i)/(8+2i) is 7/34-23/34 i

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simplify (3-5i)/(8+2i)

simplify

\frac{3 - 5 i}{8 + 2 i}

\frac{7}{34} - \frac{23}{34} i

Solution steps

\frac{3 - 5 i}{8 + 2 i}

Multiply by the conjugate

\frac{8 - 2 i}{8 - 2 i}

= \frac{( 3 - 5 i ) ( 8 - 2 i )}{( 8 + 2 i ) ( 8 - 2 i )}

Simplify

\frac{( 3 - 5 i ) ( 8 - 2 i )}{( 8 + 2 i ) ( 8 - 2 i )} : \frac{14 - 46 i}{68}

= \frac{14 - 46 i}{68}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{14}{68} + \frac{- 46}{68} i

Simplify

\frac{14}{68} + \frac{- 46}{68} i : \frac{7}{34} - \frac{23}{34} i

= \frac{7}{34} - \frac{23}{34} i

\frac{7}{8} \div \frac{9}{10}

∣ 2 + 2 i ∣

3 \frac{27}{512}

75 t + 100 t^{2}

15 \cdot 1 0^{- 3}