What is (y^2-4y-5)/(y^2+5y+4) ?

The solution to (y^2-4y-5)/(y^2+5y+4) is (y-5)/(y+4)

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simplify (y^2-4y-5)/(y^2+5y+4)

simplify

\frac{y ^{2} - 4 y - 5}{y ^{2} + 5 y + 4}

\frac{y - 5}{y + 4}

Solution steps

\frac{y ^{2} - 4 y - 5}{y ^{2} + 5 y + 4}

Factor

y^{2} - 4 y - 5 : (y + 1) (y - 5)

= \frac{( y + 1 ) ( y - 5 )}{y ^{2} + 5 y + 4}

Factor

y^{2} + 5 y + 4 : (y + 1) (y + 4)

= \frac{( y + 1 ) ( y - 5 )}{( y + 1 ) ( y + 4 )}

Cancel the common factor:

y + 1

= \frac{y - 5}{y + 4}

8 \frac{2}{4} - 1 \frac{3}{4}

2^{3} - (\frac{3}{4})^{2}

x (a + b) + m (a + b)

f (x) - 3

(5 b + 3)^{3}

What is (y^2-4y-5)/(y^2+5y+4) ?
The solution to (y^2-4y-5)/(y^2+5y+4) is (y-5)/(y+4)