What is 1/7 xy(7xy)^3 ?

The solution to 1/7 xy(7xy)^3 is 49x^4y^4

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simplify 1/7 xy(7xy)^3

simplify

\frac{1}{7} x y (7 x y)^{3}

49 x^{4} y^{4}

Solution steps

\frac{1}{7} x y (7 x y)^{3}

Simplify

(7 x y)^{3} : 343 x^{3} y^{3}

= \frac{1}{7} x y \cdot 343 x^{3} y^{3}

Simplify

x x^{3} : x^{4}

= \frac{1}{7} x^{4} y \cdot 343 y^{3}

Simplify

y y^{3} : y^{4}

= \frac{1}{7} x^{4} y^{4} \cdot 343

= \frac{1}{7} \cdot 343 x^{4} y^{4}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 343 x ^{4} y ^{4}}{7}

Multiply the numbers:

1 \cdot 343 = 343

= \frac{343 x ^{4} y ^{4}}{7}

Divide the numbers:

\frac{343}{7} = 49

= 49 x^{4} y^{4}

(2 x^{2} + 3 y)^{2}

- 3 (a + 1)^{2} + 9

- 4 \cdot (- \frac{1}{2})

- (- 3 y + 3.4)

(x^{- 3})^{3}