What are the solutions to the equation -15-22x+5x^2=0 ?

The solutions to the equation -15-22x+5x^2=0 are x=5,x=-3/5

Find the zeros of -15-22x+5x^2=0

The zeros of -15-22x+5x^2=0 are x=5,x=-3/5

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- 15 - 22 x + 5 x^{2} = 0

x = 5, x = - \frac{3}{5}

Decimal Notation

x = 5, x = - 0.6

Solution steps

- 15 - 22 x + 5 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 22 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 5 ( - 15 )}{2 \cdot 5}

(- 22)^{2} - 4 \cdot 5 (- 15) = 28

x_{1, 2} = \frac{- ( - 22 ) \pm 28}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 28}{2 \cdot 5}, x_{2} = \frac{- ( - 22 ) - 28}{2 \cdot 5}

x = \frac{- ( - 22 ) + 28}{2 \cdot 5} : 5

x = \frac{- ( - 22 ) - 28}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{5}

(2 x^{\frac{3}{2}})^{2}

7.5 h + 100 = 12.75 h + 80

\frac{x ^{8}}{x ^{- 2}}

\frac{9 x ^{2} + 4 y ^{2} - 12 x y}{4 y ^{2} - 9 x ^{2}}

2 a + \frac{1}{2} = \frac{1}{4}

What are the solutions to the equation -15-22x+5x^2=0 ?
The solutions to the equation -15-22x+5x^2=0 are x=5,x=-3/5
Find the zeros of -15-22x+5x^2=0
The zeros of -15-22x+5x^2=0 are x=5,x=-3/5