What is (x^2+5x+4)/(x^2+3x-4) ?

The solution to (x^2+5x+4)/(x^2+3x-4) is (x+1)/(x-1)

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simplify (x^2+5x+4)/(x^2+3x-4)

simplify

\frac{x ^{2} + 5 x + 4}{x ^{2} + 3 x - 4}

\frac{x + 1}{x - 1}

Solution steps

\frac{x ^{2} + 5 x + 4}{x ^{2} + 3 x - 4}

Factor

x^{2} + 5 x + 4 : (x + 1) (x + 4)

= \frac{( x + 1 ) ( x + 4 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x + 1 ) ( x + 4 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{x + 1}{x - 1}

10 x + 3 y + z - (5 x - 8 y + 3 z + 5 x - 2 y - 5 z)

(- 3) (4)

2 x^{2} + 4 x - 4

0.004

3 + \frac{3}{5}

What is (x^2+5x+4)/(x^2+3x-4) ?
The solution to (x^2+5x+4)/(x^2+3x-4) is (x+1)/(x-1)