What is factor b^2+5b+4 ?

The solution to factor b^2+5b+4 is (b+1)(b+4)

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factor b^2+5b+4

factor

b^{2} + 5 b + 4

(b + 1) (b + 4)

Solution steps

b^{2} + 5 b + 4

Break the expression into groups

= (b^{2} + b) + (4 b + 4)

Factor out

b

from

b^{2} + b : b (b + 1)

Factor out

4

from

4 b + 4 : 4 (b + 1)

= b (b + 1) + 4 (b + 1)

Factor out common term

b + 1

= (b + 1) (b + 4)

\frac{15 t ^{9}}{( 5 t ^{4} ) ^{3}}

121 x^{2} - 64

\frac{3}{5} + \frac{7}{8}

6 \cdot 7128

\frac{3 + \frac{1}{x}}{1 + x}