What is (2x^4-x^3-3+7x)/(2x+3) ?

The solution to (2x^4-x^3-3+7x)/(2x+3) is x^3-2x^2+3x-1

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simplify (2x^4-x^3-3+7x)/(2x+3)

simplify

\frac{2 x ^{4} - x ^{3} - 3 + 7 x}{2 x + 3}

x^{3} - 2 x^{2} + 3 x - 1

Solution steps

\frac{2 x ^{4} - x ^{3} - 3 + 7 x}{2 x + 3}

Factor

2 x^{4} - x^{3} - 3 + 7 x : (2 x + 3) (x^{3} - 2 x^{2} + 3 x - 1)

= \frac{( 2 x + 3 ) ( x ^{3} - 2 x ^{2} + 3 x - 1 )}{2 x + 3}

Cancel the common factor:

2 x + 3

= x^{3} - 2 x^{2} + 3 x - 1

\frac{1}{3} \div \frac{13}{9}

(x + 2)^{2} - 2 (x + 2)

(- 4 x + 1) - (- 7 x^{2} + 4 x + 2)

(a + h) (a + h) (a + h)

7 + 48

What is (2x^4-x^3-3+7x)/(2x+3) ?
The solution to (2x^4-x^3-3+7x)/(2x+3) is x^3-2x^2+3x-1