What are the solutions to the equation 49x^2+56x+16=0 ?

The solutions to the equation 49x^2+56x+16=0 are x=-4/7

Find the zeros of 49x^2+56x+16=0

The zeros of 49x^2+56x+16=0 are x=-4/7

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49 x^{2} + 56 x + 16 = 0

x = - \frac{4}{7}

Decimal Notation

x = - 0.57142 \dots

Solution steps

49 x^{2} + 56 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 49 \cdot 16}{2 \cdot 49}

5 6^{2} - 4 \cdot 49 \cdot 16 = 0

x_{1, 2} = \frac{- 56 \pm 0}{2 \cdot 49}

x = \frac{- 56}{2 \cdot 49}

\frac{- 56}{2 \cdot 49} = - \frac{4}{7}

x = - \frac{4}{7}

The solution to the quadratic equation is:

x = - \frac{4}{7}

\frac{1}{6} + \frac{1}{8}

100 = \frac{- 32 x ^{2}}{( 55 ) ^{2}} + x + 210

13 = t + 7

2 a a b^{2} - 3 a + 3 b a^{3}

- 6 x + 7 > x + 9

What are the solutions to the equation 49x^2+56x+16=0 ?
The solutions to the equation 49x^2+56x+16=0 are x=-4/7
Find the zeros of 49x^2+56x+16=0
The zeros of 49x^2+56x+16=0 are x=-4/7