What is expand (2x^2-5x+3)(3x^2-x-1) ?

The solution to expand (2x^2-5x+3)(3x^2-x-1) is 6x^4-17x^3+12x^2+2x-3

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expand (2x^2-5x+3)(3x^2-x-1)

expand

(2 x^{2} - 5 x + 3) (3 x^{2} - x - 1)

6 x^{4} - 17 x^{3} + 12 x^{2} + 2 x - 3

Solution steps

(2 x^{2} - 5 x + 3) (3 x^{2} - x - 1)

Distribute parentheses

= 2 x^{2} \cdot 3 x^{2} + 2 x^{2} (- x) + 2 x^{2} (- 1) - 5 x \cdot 3 x^{2} - 5 x (- x) - 5 x (- 1) + 3 \cdot 3 x^{2} + 3 (- x) + 3 (- 1)

Simplify

2 x^{2} \cdot 3 x^{2} + 2 x^{2} (- x) + 2 x^{2} (- 1) - 5 x \cdot 3 x^{2} - 5 x (- x) - 5 x (- 1) + 3 \cdot 3 x^{2} + 3 (- x) + 3 (- 1) : 6 x^{4} - 17 x^{3} + 12 x^{2} + 2 x - 3

= 6 x^{4} - 17 x^{3} + 12 x^{2} + 2 x - 3

x + 6 x - x

3 y^{- 2}

8 (x - 6) - 2 (x - 2)

\frac{9}{16} - \frac{11}{20}

(5) (- 4)

What is expand (2x^2-5x+3)(3x^2-x-1) ?
The solution to expand (2x^2-5x+3)(3x^2-x-1) is 6x^4-17x^3+12x^2+2x-3