What is ((2x^4y)/(4x^3y))^{-3} ?

The solution to ((2x^4y)/(4x^3y))^{-3} is 8/(x^3)

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simplify ((2x^4y)/(4x^3y))^{-3}

simplify

(\frac{2 x ^{4} y}{4 x ^{3} y})^{- 3}

\frac{8}{x ^{3}}

Solution steps

(\frac{2 x ^{4} y}{4 x ^{3} y})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 x ^{4} y}{4 x ^{3} y})^{- 3} = \frac{1}{( \frac{2 x ^{4} y}{4 x ^{3} y} ) ^{3}}

= \frac{1}{( \frac{2 x ^{4} y}{4 x ^{3} y} ) ^{3}}

Simplify

(\frac{2 x ^{4} y}{4 x ^{3} y})^{3} : \frac{x ^{3}}{8}

= \frac{1}{\frac{x ^{3}}{8}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{8}{x ^{3}}

(- 9) (- 8)

(- 2) - (- 8)

(- 2) - (- 4)

\frac{11}{6} + (- \frac{11}{10})

50 + 128

What is ((2x^4y)/(4x^3y))^{-3} ?
The solution to ((2x^4y)/(4x^3y))^{-3} is 8/(x^3)