What is (-2x^{-5}y^3)^{-4} ?

The solution to (-2x^{-5}y^3)^{-4} is (x^{20})/(16y^{12)}

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simplify (-2x^{-5}y^3)^{-4}

simplify

(- 2 x^{- 5} y^{3})^{- 4}

\frac{x ^{20}}{16 y ^{12}}

Solution steps

(- 2 x^{- 5} y^{3})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(- 2 x^{- 5} y^{3})^{- 4} = \frac{1}{( - 2 x ^{- 5} y ^{3} ) ^{4}}

= \frac{1}{( - 2 x ^{- 5} y ^{3} ) ^{4}}

Simplify

(- 2 x^{- 5} y^{3})^{4} : \frac{16 y ^{12}}{x ^{20}}

= \frac{1}{\frac{16 y ^{12}}{x ^{20}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{20}}{16 y ^{12}}

- (- m - 2 m - 8 m) - (- 4 m - m)

1 \frac{3}{4} + \frac{1}{2}

(6 - 3 x) (6 + 3 x)

\frac{4 \cdot 3 + 18 x}{9 - 12}

What is (-2x^{-5}y^3)^{-4} ?
The solution to (-2x^{-5}y^3)^{-4} is (x^{20})/(16y^{12)}