What is expand (2x+3)(4x^2+2x-5) ?

The solution to expand (2x+3)(4x^2+2x-5) is 8x^3+16x^2-4x-15

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expand (2x+3)(4x^2+2x-5)

expand

(2 x + 3) (4 x^{2} + 2 x - 5)

8 x^{3} + 16 x^{2} - 4 x - 15

Solution steps

(2 x + 3) (4 x^{2} + 2 x - 5)

Distribute parentheses

= 2 x \cdot 4 x^{2} + 2 x \cdot 2 x + 2 x (- 5) + 3 \cdot 4 x^{2} + 3 \cdot 2 x + 3 (- 5)

Simplify

2 x \cdot 4 x^{2} + 2 x \cdot 2 x + 2 x (- 5) + 3 \cdot 4 x^{2} + 3 \cdot 2 x + 3 (- 5) : 8 x^{3} + 16 x^{2} - 4 x - 15

= 8 x^{3} + 16 x^{2} - 4 x - 15

\frac{5}{8} + \frac{1}{10}

2 x^{2} \cdot 1

3 + 8

1 - sin^{2} (x)

5 c + 2 (4 a - 2 b) - 3 (2 a - 2 b - c)

What is expand (2x+3)(4x^2+2x-5) ?
The solution to expand (2x+3)(4x^2+2x-5) is 8x^3+16x^2-4x-15