What are the solutions to the equation x^2+8x-65=x-5 ?

The solutions to the equation x^2+8x-65=x-5 are x=5,x=-12

Find the zeros of x^2+8x-65=x-5

The zeros of x^2+8x-65=x-5 are x=5,x=-12

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x^{2} + 8 x - 65 = x - 5

x = 5, x = - 12

Solution steps

x^{2} + 8 x - 65 = x - 5

Move

5

to the left side

x^{2} + 8 x - 60 = x

Move

x

to the left side

x^{2} + 7 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 60) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 1}, x_{2} = \frac{- 7 - 17}{2 \cdot 1}

x = \frac{- 7 + 17}{2 \cdot 1} : 5

x = \frac{- 7 - 17}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 5, x = - 12

5 \cdot 4 \cdot 3 \cdot 2 \cdot 1

r - 7 = - 3

\frac{3 ^{- 1}}{( - 5 ) ^{0}}

∣ 4 x + 3 ∣ - 2 = - 1

4 x - x + 6 = 2 (x + 1) + x

What are the solutions to the equation x^2+8x-65=x-5 ?
The solutions to the equation x^2+8x-65=x-5 are x=5,x=-12
Find the zeros of x^2+8x-65=x-5
The zeros of x^2+8x-65=x-5 are x=5,x=-12