What is (y/(3z^3))^{-2} ?

The solution to (y/(3z^3))^{-2} is (9z^6)/(y^2)

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simplify (y/(3z^3))^{-2}

simplify

(\frac{y}{3 z ^{3}})^{- 2}

\frac{9 z ^{6}}{y ^{2}}

Solution steps

(\frac{y}{3 z ^{3}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{y}{3 z ^{3}})^{- 2} = \frac{1}{( \frac{y}{3 z ^{3}} ) ^{2}}

= \frac{1}{( \frac{y}{3 z ^{3}} ) ^{2}}

Simplify

(\frac{y}{3 z ^{3}})^{2} : \frac{y ^{2}}{9 z ^{6}}

= \frac{1}{\frac{y ^{2}}{9 z ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{9 z ^{6}}{y ^{2}}

\frac{1 0 ^{6}}{( 1 0 ^{10} ) ^{- 2}}

(2 a + 6 b) (2 a - 6 b)

(1 - cos^{2} (x)) sec^{2} (x)

(3 x - 3)^{2} - 7 (3 x - 3) + 15

18 x y - 30 x^{2}