What is factor 27x^6-8 ?

The solution to factor 27x^6-8 is (3x^2-2)(9x^4+6x^2+4)

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factor 27x^6-8

factor

27 x^{6} - 8

(3 x^{2} - 2) (9 x^{4} + 6 x^{2} + 4)

Solution steps

27 x^{6} - 8

Apply exponent rules

= (3 x^{2})^{3} - 2^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(3 x^{2})^{3} - 2^{3} = (3 x^{2} - 2) (3^{2} x^{4} + 2 \cdot 3 x^{2} + 2^{2})

= (3 x^{2} - 2) (3^{2} x^{4} + 2 \cdot 3 x^{2} + 2^{2})

Simplify

(3 x^{2} - 2) (3^{2} x^{4} + 2 \cdot 3 x^{2} + 2^{2}) : (3 x^{2} - 2) (9 x^{4} + 6 x^{2} + 4)

= (3 x^{2} - 2) (9 x^{4} + 6 x^{2} + 4)

(2 + i) (3 + 2 i)

6 (4 y + 7 z)

(8 b + 9) - (7 b - 5)

8 x^{3} + 8

\frac{x - 1}{x - 1}

What is factor 27x^6-8 ?
The solution to factor 27x^6-8 is (3x^2-2)(9x^4+6x^2+4)