What is ((3c+2))/1+(c-1)/c ?

The solution to ((3c+2))/1+(c-1)/c is (3c^2+3c-1)/c

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simplify ((3c+2))/1+(c-1)/c

simplify

\frac{( 3 c + 2 )}{1} + \frac{c - 1}{c}

\frac{3 c ^{2} + 3 c - 1}{c}

Solution steps

\frac{3 c + 2}{1} + \frac{c - 1}{c}

Least Common Multiplier of

1, c : c

Adjust Fractions based on the LCM

= \frac{( 3 c + 2 ) c}{c} + \frac{c - 1}{c}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{( 3 c + 2 ) c + c - 1}{c}

Simplify

(3 c + 2) c + c - 1 : 3 c^{2} + 3 c - 1

= \frac{3 c ^{2} + 3 c - 1}{c}

i^{7} (1 + i^{2})

\frac{90}{12}

4 x^{4} - 64

7 \frac{3}{5} - 2 \frac{3}{10}

What is ((3c+2))/1+(c-1)/c ?
The solution to ((3c+2))/1+(c-1)/c is (3c^2+3c-1)/c