What are the solutions to the equation 50=-5x^2+200 ?

The solutions to the equation 50=-5x^2+200 are x=sqrt(30),x=-sqrt(30)

Find the zeros of 50=-5x^2+200

The zeros of 50=-5x^2+200 are x=sqrt(30),x=-sqrt(30)

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50 = - 5 x^{2} + 200

x = 30, x = - 30

Solution steps

50 = - 5 x^{2} + 200

Switch sides

- 5 x^{2} + 200 = 50

Move

200

to the right side

- 5 x^{2} = - 150

Divide both sides by

- 5

x^{2} = 30

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 30, x = - 30

(\frac{2 a ^{2}}{8 a ^{- 2}})^{- \frac{1}{2}}

q^{3} + a^{3}

- 3 x^{2} > 2 x - 1

\frac{a ^{4}}{a ^{2}}

64 a^{3} + 125

What are the solutions to the equation 50=-5x^2+200 ?
The solutions to the equation 50=-5x^2+200 are x=sqrt(30),x=-sqrt(30)
Find the zeros of 50=-5x^2+200
The zeros of 50=-5x^2+200 are x=sqrt(30),x=-sqrt(30)