What is (3+2i)-(6-4i) ?

The solution to (3+2i)-(6-4i) is -3+6i

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simplify (3+2i)-(6-4i)

simplify

(3 + 2 i) - (6 - 4 i)

- 3 + 6 i

Solution steps

(3 + 2 i) - (6 - 4 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (3 - 6) + (2 - (- 4)) i

Simplify

(3 - 6) + (2 - (- 4)) i : - 3 + 6 i

= - 3 + 6 i

(x - 3) + 3 + 2

(- 10) (- 7) (- 4)

(2 x^{2} - 3 x)^{3}

5 \frac{4}{9}

\frac{11}{12} + (- \frac{7}{12})