What is 1/(a^{-1)+b^{-1}} ?

The solution to 1/(a^{-1)+b^{-1}} is (ab)/(b+a)

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simplify 1/(a^{-1)+b^{-1}}

simplify

\frac{1}{a ^{- 1} + b ^{- 1}}

\frac{ab}{b + a}

Solution steps

\frac{1}{a ^{- 1} + b ^{- 1}}

Simplify

a^{- 1} + b^{- 1} : \frac{b + a}{ab}

= \frac{1}{\frac{b + a}{ab}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{ab}{b + a}

4 x (x)

\frac{37}{9}

(ab)^{4}

- \frac{9}{20} + \frac{1}{16}

\frac{2}{2} + \frac{1}{3}