What is the answer to 7/3 (2x-1)= 1/5 x+2/5 (4-3x) ?

The answer to 7/3 (2x-1)= 1/5 x+2/5 (4-3x) is x= 59/85

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7/3 (2x-1)= 1/5 x+2/5 (4-3x)

\frac{7}{3} (2 x - 1) = \frac{1}{5} x + \frac{2}{5} (4 - 3 x)

x = \frac{59}{85}

Solution steps

\frac{7}{3} (2 x - 1) = \frac{1}{5} x + \frac{2}{5} (4 - 3 x)

Expand

\frac{7}{3} (2 x - 1) : \frac{14}{3} x - \frac{7}{3}

Expand

\frac{1}{5} x + \frac{2}{5} (4 - 3 x) : - x + \frac{8}{5}

\frac{14}{3} x - \frac{7}{3} = - x + \frac{8}{5}

Move

\frac{7}{3}

to the right side

\frac{14}{3} x = - x + \frac{59}{15}

Move

x

to the left side

\frac{17}{3} x = \frac{59}{15}

Multiply both sides by

3

17 x = \frac{59}{5}

Divide both sides by

17

x = \frac{59}{85}

(x - 5) (x - 2) (x + 1) > 0

x y + 6 y - 8 x - 48

(- \frac{45}{49}) (\frac{48}{18})

x^{19}

\frac{9}{x + 8} \leq 10

What is the answer to 7/3 (2x-1)= 1/5 x+2/5 (4-3x) ?
The answer to 7/3 (2x-1)= 1/5 x+2/5 (4-3x) is x= 59/85
Solve for x: 7/3 (2x-1)= 1/5 x+2/5 (4-3x)
The solution is x= 59/85