What is (5p^2q^{-4})^{-3} ?

The solution to (5p^2q^{-4})^{-3} is (q^{12})/(125p^6)

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simplify (5p^2q^{-4})^{-3}

simplify

(5 p^{2} q^{- 4})^{- 3}

\frac{q ^{12}}{125 p ^{6}}

Solution steps

(5 p^{2} q^{- 4})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(5 p^{2} q^{- 4})^{- 3} = \frac{1}{( 5 p ^{2} q ^{- 4} ) ^{3}}

= \frac{1}{( 5 p ^{2} q ^{- 4} ) ^{3}}

Simplify

(5 p^{2} q^{- 4})^{3} : \frac{125 p ^{6}}{q ^{12}}

= \frac{1}{\frac{125 p ^{6}}{q ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{q ^{12}}{125 p ^{6}}

y^{3} \cdot y^{4}

(3 a - 2 b^{2})^{3}

\frac{- 2.9 9 ^{3} + 27}{- 2.99 + 3}

143 + 305 \cdot 70 He ll a o

\frac{5}{9} \cdot (- 32)

What is (5p^2q^{-4})^{-3} ?
The solution to (5p^2q^{-4})^{-3} is (q^{12})/(125p^6)