What is (2x^2-x)/(2x^2+x-1) ?

The solution to (2x^2-x)/(2x^2+x-1) is x/(x+1)

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simplify (2x^2-x)/(2x^2+x-1)

simplify

\frac{2 x ^{2} - x}{2 x ^{2} + x - 1}

\frac{x}{x + 1}

Solution steps

\frac{2 x ^{2} - x}{2 x ^{2} + x - 1}

Factor

2 x^{2} - x : x (2 x - 1)

= \frac{x ( 2 x - 1 )}{2 x ^{2} + x - 1}

Factor

2 x^{2} + x - 1 : (2 x - 1) (x + 1)

= \frac{x ( 2 x - 1 )}{( 2 x - 1 ) ( x + 1 )}

Cancel the common factor:

2 x - 1

= \frac{x}{x + 1}

x y^{2} + x^{3} y^{4} + x^{5} y^{3}

(5 x^{2} - x + 2)^{2}

- 5 (2 x^{2} - 4 x - 12) - 5

\frac{4 - x}{x ^{2} - 16}

11 \frac{1}{2}