What is (x^3-49x)/(x^4-7x^3) ?

The solution to (x^3-49x)/(x^4-7x^3) is (x+7)/(x^2)

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simplify (x^3-49x)/(x^4-7x^3)

simplify

\frac{x ^{3} - 49 x}{x ^{4} - 7 x ^{3}}

\frac{x + 7}{x ^{2}}

Solution steps

\frac{x ^{3} - 49 x}{x ^{4} - 7 x ^{3}}

Factor

x^{3} - 49 x : x (x + 7) (x - 7)

= \frac{x ( x + 7 ) ( x - 7 )}{x ^{4} - 7 x ^{3}}

Factor

x^{4} - 7 x^{3} : x^{3} (x - 7)

= \frac{x ( x + 7 ) ( x - 7 )}{x ^{3} ( x - 7 )}

Cancel the common factor:

x - 7

= \frac{x ( x + 7 )}{x ^{3}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{3} = x x^{2}

= \frac{x ( x + 7 )}{x x ^{2}}

Cancel the common factor:

x

= \frac{x + 7}{x ^{2}}

1854

f (x) + f (2 x - 1)

(+ 9) + (- 3)

(3^{4})^{- 4}

\frac{4}{7} - \frac{2}{5}

What is (x^3-49x)/(x^4-7x^3) ?
The solution to (x^3-49x)/(x^4-7x^3) is (x+7)/(x^2)