What is (x^2-4x-5)/(x^2+3x+2) ?

The solution to (x^2-4x-5)/(x^2+3x+2) is (x-5)/(x+2)

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simplify (x^2-4x-5)/(x^2+3x+2)

simplify

\frac{x ^{2} - 4 x - 5}{x ^{2} + 3 x + 2}

\frac{x - 5}{x + 2}

Solution steps

\frac{x ^{2} - 4 x - 5}{x ^{2} + 3 x + 2}

Factor

x^{2} - 4 x - 5 : (x + 1) (x - 5)

= \frac{( x + 1 ) ( x - 5 )}{x ^{2} + 3 x + 2}

Factor

x^{2} + 3 x + 2 : (x + 1) (x + 2)

= \frac{( x + 1 ) ( x - 5 )}{( x + 1 ) ( x + 2 )}

Cancel the common factor:

x + 1

= \frac{x - 5}{x + 2}

\frac{1}{1 + 3 i} + \frac{1}{1 + 6 i}

- \frac{12}{20} \div \frac{2}{5}

225 \div 25

0. 4^{6}

(a^{2} + b)^{2} - (a^{2} - b)^{2}

What is (x^2-4x-5)/(x^2+3x+2) ?
The solution to (x^2-4x-5)/(x^2+3x+2) is (x-5)/(x+2)