What is (t^2-9)/(2t^2+7t+3) ?

The solution to (t^2-9)/(2t^2+7t+3) is (t-3)/(2t+1)

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simplify (t^2-9)/(2t^2+7t+3)

simplify

\frac{t ^{2} - 9}{2 t ^{2} + 7 t + 3}

\frac{t - 3}{2 t + 1}

Solution steps

\frac{t ^{2} - 9}{2 t ^{2} + 7 t + 3}

Factor

t^{2} - 9 : (t + 3) (t - 3)

= \frac{( t + 3 ) ( t - 3 )}{2 t ^{2} + 7 t + 3}

Factor

2 t^{2} + 7 t + 3 : (2 t + 1) (t + 3)

= \frac{( t + 3 ) ( t - 3 )}{( 2 t + 1 ) ( t + 3 )}

Cancel the common factor:

t + 3

= \frac{t - 3}{2 t + 1}

2 (3 + 8)

0 (- x)

\frac{2 - ( 18 - 3 x )}{( 18 - 3 x ) + 1}

\frac{3 + ( - 1 )}{2}

What is (t^2-9)/(2t^2+7t+3) ?
The solution to (t^2-9)/(2t^2+7t+3) is (t-3)/(2t+1)