What is (t^4-1)/(t^3-1) ?

The solution to (t^4-1)/(t^3-1) is ((t^2+1)(t+1))/(t^2+t+1)

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simplify (t^4-1)/(t^3-1)

simplify

\frac{t ^{4} - 1}{t ^{3} - 1}

\frac{( t ^{2} + 1 ) ( t + 1 )}{t ^{2} + t + 1}

Solution steps

\frac{t ^{4} - 1}{t ^{3} - 1}

Factor

t^{4} - 1 : (t^{2} + 1) (t + 1) (t - 1)

= \frac{( t ^{2} + 1 ) ( t + 1 ) ( t - 1 )}{t ^{3} - 1}

Factor

t^{3} - 1 : (t - 1) (t^{2} + t + 1)

= \frac{( t ^{2} + 1 ) ( t + 1 ) ( t - 1 )}{( t - 1 ) ( t ^{2} + t + 1 )}

Cancel the common factor:

t - 1

= \frac{( t ^{2} + 1 ) ( t + 1 )}{t ^{2} + t + 1}

2 a - (2 + 5 a)

(- 3 + 7 i) \cdot (2 + 5 i)

- (- \frac{( x - 2 )}{4} + 1)

(x + y)^{3} - (x + y)^{4} z

\frac{9}{6} - \frac{4}{3}

What is (t^4-1)/(t^3-1) ?
The solution to (t^4-1)/(t^3-1) is ((t^2+1)(t+1))/(t^2+t+1)