What is 100+x<= 41-6x<= 121+x ?

The solution to 100+x<= 41-6x<= 121+x is -80/7 <= x<=-59/7

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100+x<= 41-6x<= 121+x

100 + x \leq 41 - 6 x \leq 121 + x

- \frac{80}{7} \leq x \leq - \frac{59}{7}

Solution steps

100 + x \leq 41 - 6 x \leq 121 + x

a \leq u \leq b

then

a \leq u and u \leq b

100 + x \leq 41 - 6 x and 41 - 6 x \leq 121 + x

100 + x \leq 41 - 6 x : x \leq - \frac{59}{7}

41 - 6 x \leq 121 + x : x \geq - \frac{80}{7}

Combine the intervals

x \leq - \frac{59}{7} and x \geq - \frac{80}{7}

Merge Overlapping Intervals

- \frac{80}{7} \leq x \leq - \frac{59}{7}

\frac{e ^{x}}{e ^{x} + e ^{y}} + \frac{e ^{y}}{e ^{x} + e ^{y}}

6 x^{3} - 12 x^{2} + 24 x^{2}

\frac{5}{3} - \frac{1}{2}

c - 7 = - 7

∣ 6 x ∣ < 6

What is 100+x<= 41-6x<= 121+x ?
The solution to 100+x<= 41-6x<= 121+x is -80/7 <= x<=-59/7