What is expand (x^2+2x-3)(x^2+3x-4) ?

The solution to expand (x^2+2x-3)(x^2+3x-4) is x^4+5x^3-x^2-17x+12

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expand (x^2+2x-3)(x^2+3x-4)

expand

(x^{2} + 2 x - 3) (x^{2} + 3 x - 4)

x^{4} + 5 x^{3} - x^{2} - 17 x + 12

Solution steps

(x^{2} + 2 x - 3) (x^{2} + 3 x - 4)

Distribute parentheses

= x^{2} x^{2} + x^{2} \cdot 3 x + x^{2} (- 4) + 2 x x^{2} + 2 x \cdot 3 x + 2 x (- 4) - 3 x^{2} - 3 \cdot 3 x - 3 (- 4)

Simplify

x^{2} x^{2} + x^{2} \cdot 3 x + x^{2} (- 4) + 2 x x^{2} + 2 x \cdot 3 x + 2 x (- 4) - 3 x^{2} - 3 \cdot 3 x - 3 (- 4) : x^{4} + 5 x^{3} - x^{2} - 17 x + 12

= x^{4} + 5 x^{3} - x^{2} - 17 x + 12

5 p (3 q + 4)

\frac{5}{4} \div \frac{3}{5}

(x^{3} - 2)^{3} - 2

\frac{5 ^{- 1}}{- 9 ^{0}}

312 - 27

What is expand (x^2+2x-3)(x^2+3x-4) ?
The solution to expand (x^2+2x-3)(x^2+3x-4) is x^4+5x^3-x^2-17x+12