What is (x^2-3x+2)/(x^2-1) ?

The solution to (x^2-3x+2)/(x^2-1) is (x-2)/(x+1)

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simplify (x^2-3x+2)/(x^2-1)

simplify

\frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

\frac{x - 2}{x + 1}

Solution steps

\frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

Factor

x^{2} - 3 x + 2 : (x - 1) (x - 2)

= \frac{( x - 1 ) ( x - 2 )}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x - 1 ) ( x - 2 )}{( x + 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x - 2}{x + 1}

3 x - 5 y + x - y

(sec (x) - cos (x)) cot (x)

(- 4 + 3 i)^{2}

(x - 2) (x^{2} + 2 x + 1)

- n^{4} - n^{2} + 20