What is expand n(n+1)(2n+1)(3n^2+3n-1) ?

The solution to expand n(n+1)(2n+1)(3n^2+3n-1) is 6n^5+15n^4+10n^3-n

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expand n(n+1)(2n+1)(3n^2+3n-1)

expand

n (n + 1) (2 n + 1) (3 n^{2} + 3 n - 1)

6 n^{5} + 15 n^{4} + 10 n^{3} - n

Solution steps

n (n + 1) (2 n + 1) (3 n^{2} + 3 n - 1)

Expand

n (n + 1) (2 n + 1) (3 n^{2} + 3 n - 1) : n (2 n^{2} + 3 n + 1) (3 n^{2} + 3 n - 1)

= n (2 n^{2} + 3 n + 1) (3 n^{2} + 3 n - 1)

Expand

(2 n^{2} + 3 n + 1) (3 n^{2} + 3 n - 1) : 6 n^{4} + 15 n^{3} + 10 n^{2} - 1

= n (6 n^{4} + 15 n^{3} + 10 n^{2} - 1)

Distribute parentheses

= n \cdot 6 n^{4} + n \cdot 15 n^{3} + n \cdot 10 n^{2} + n (- 1)

Simplify

n \cdot 6 n^{4} + n \cdot 15 n^{3} + n \cdot 10 n^{2} + n (- 1) : 6 n^{5} + 15 n^{4} + 10 n^{3} - n

= 6 n^{5} + 15 n^{4} + 10 n^{3} - n

(x - 4) (2 x + x^{2}) (x - 1)

- 3 - ∣ - 3 ∣

(x^{2})

(- 6) - (- 6)

(x^{2} + 5) - 3

What is expand n(n+1)(2n+1)(3n^2+3n-1) ?
The solution to expand n(n+1)(2n+1)(3n^2+3n-1) is 6n^5+15n^4+10n^3-n