What is (4x^2-2xy+5)-(x^2+xy-1) ?

The solution to (4x^2-2xy+5)-(x^2+xy-1) is 3x^2-3xy+6

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simplify (4x^2-2xy+5)-(x^2+xy-1)

simplify

(4 x^{2} - 2 x y + 5) - (x^{2} + x y - 1)

3 x^{2} - 3 x y + 6

Solution steps

(4 x^{2} - 2 x y + 5) - (x^{2} + x y - 1)

Apply rule:

(a) = a

(4 x^{2} - 2 x y + 5) = 4 x^{2} - 2 x y + 5

= 4 x^{2} - 2 x y + 5 - (x^{2} + x y - 1)

Apply the distributive law:

- (a + b) = - a - b

- (x^{2} + x y - 1) = - x^{2} - x y + 1

= 4 x^{2} - 2 x y + 5 - x^{2} - x y + 1

Group like terms

= 4 x^{2} - x^{2} - 2 x y - x y + 5 + 1

Add similar elements:

4 x^{2} - x^{2} = 3 x^{2}

= 3 x^{2} - 2 x y - x y + 5 + 1

Add similar elements:

- 2 x y - x y = - 3 x y

= 3 x^{2} - 3 x y + 5 + 1

Add the numbers:

5 + 1 = 6

= 3 x^{2} - 3 x y + 6

\frac{x ^{2}}{x ^{- 1}}

\frac{9}{121}

\frac{1}{15} + \frac{8}{9}

(- 2 + 4 i) (- 2 - 4 i)

What is (4x^2-2xy+5)-(x^2+xy-1) ?
The solution to (4x^2-2xy+5)-(x^2+xy-1) is 3x^2-3xy+6