What is x(x-4)(x+pi)^2(x-sqrt(2))>= 0 ?

The solution to x(x-4)(x+pi)^2(x-sqrt(2))>= 0 is x=-pi\lor 0 = 4

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x(x-4)(x+pi)^2(x-sqrt(2))>= 0

x (x - 4) (x + π)^{2} (x - 2) \geq 0

x = - π or 0 \leq x \leq 2 or x \geq 4

Interval Notation

x = - π \cup [0, 2] \cup [4, \infty)

Decimal Notation

x = - 3.14159 \dots or 0 \leq x \leq 1.41421 \dots or x \geq 4

Solution steps

x (x - 4) (x + π)^{2} (x - 2) \geq 0

Identify the intervals

x = - π or 0 \leq x \leq 2 or x \geq 4

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What is x(x-4)(x+pi)^2(x-sqrt(2))>= 0 ?
The solution to x(x-4)(x+pi)^2(x-sqrt(2))>= 0 is x=-pi\lor 0<= x<= sqrt(2)\lor x>= 4