What is x(x-4)(x+pi)^2(x-sqrt(2))>= 0 ?

The solution to x(x-4)(x+pi)^2(x-sqrt(2))>= 0 is x=-pi\lor 0 = 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x(x-4)(x+pi)^2(x-sqrt(2))>= 0

x (x - 4) (x + π)^{2} (x - 2) \geq 0

x = - π or 0 \leq x \leq 2 or x \geq 4

Solution steps

x (x - 4) (x + π)^{2} (x - 2) \geq 0

Identify the intervals

x = - π or 0 \leq x \leq 2 or x \geq 4

3 x + 5 = x + 13

119

2 m^{2} - 9 m - 11

∣ x - 3 ∣ + ∣ x - 5 ∣ = ∣ x + 7 ∣

x^{3} + 5 x^{2} - 24 x

What is x(x-4)(x+pi)^2(x-sqrt(2))>= 0 ?
The solution to x(x-4)(x+pi)^2(x-sqrt(2))>= 0 is x=-pi\lor 0<= x<= sqrt(2)\lor x>= 4