What is 2y*3x^{-1}y^4 ?

The solution to 2y*3x^{-1}y^4 is (6y^5)/x

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simplify 2y*3x^{-1}y^4

simplify

2 y \cdot 3 x^{- 1} y^{4}

\frac{6 y ^{5}}{x}

Solution steps

2 y \cdot 3 x^{- 1} y^{4}

Multiply the numbers:

2 \cdot 3 = 6

= 6 y x^{- 1} y^{4}

Simplify

y y^{4} : y^{5}

= 6 y^{5} x^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

x^{- 1} = \frac{1}{x}

= 6 \cdot \frac{1}{x} y^{5}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 6 y ^{5}}{x}

Multiply the numbers:

1 \cdot 6 = 6

= \frac{6 y ^{5}}{x}

1 - 4 sin^{2} (x)

\frac{1}{- 1 ^{2}}

\frac{2}{7 + 5}

8 + \frac{8}{3}

\frac{2}{3} \div \frac{4}{9}