What is factor 4x^4-9x^2-6x-1 ?

The solution to factor 4x^4-9x^2-6x-1 is (2x+1)(x+1)(2x^2-3x-1)

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factor 4x^4-9x^2-6x-1

factor

4 x^{4} - 9 x^{2} - 6 x - 1

(2 x + 1) (x + 1) (2 x^{2} - 3 x - 1)

Solution steps

4 x^{4} - 9 x^{2} - 6 x - 1

Factor

- 9 x^{2} - 6 x - 1 : - (3 x + 1)^{2}

= 4 x^{4} - (3 x + 1)^{2}

Simplify

4 x^{4} : (2 x^{2})^{2}

= (2 x^{2})^{2} - (3 x + 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 x^{2})^{2} - (3 x + 1)^{2} = (2 x^{2} + (3 x + 1)) (2 x^{2} - (3 x + 1))

= (2 x^{2} + (3 x + 1)) (2 x^{2} - (3 x + 1))

Simplify

(2 x^{2} + (3 x + 1)) (2 x^{2} - (3 x + 1)) : (2 x^{2} + 3 x + 1) (2 x^{2} - 3 x - 1)

= (2 x^{2} + 3 x + 1) (2 x^{2} - 3 x - 1)

Factor

2 x^{2} + 3 x + 1 : (2 x + 1) (x + 1)

= (2 x + 1) (x + 1) (2 x^{2} - 3 x - 1)

(x^{2} - 4 x + 3) (- 2 x)

(- 6)^{2} \cdot (- 6)^{5}

1.00 1^{2}

\frac{x ^{2} - 7 x + 10}{x ^{3} - 125}

8 \cdot 1 0^{- 8}

What is factor 4x^4-9x^2-6x-1 ?
The solution to factor 4x^4-9x^2-6x-1 is (2x+1)(x+1)(2x^2-3x-1)