What are the solutions to the equation 6y^2-5y-6=0 ?

The solutions to the equation 6y^2-5y-6=0 are y= 3/2 ,y=-2/3

Find the zeros of 6y^2-5y-6=0

The zeros of 6y^2-5y-6=0 are y= 3/2 ,y=-2/3

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6 y^{2} - 5 y - 6 = 0

y = \frac{3}{2}, y = - \frac{2}{3}

Solution steps

6 y^{2} - 5 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 6) = 13

y_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 6}, y_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 6}

y = \frac{- ( - 5 ) + 13}{2 \cdot 6} : \frac{3}{2}

y = \frac{- ( - 5 ) - 13}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

y = \frac{3}{2}, y = - \frac{2}{3}

y^{3} - 8 z^{3}

8 - \frac{16}{3}

\frac{1}{6} \cdot 3

\frac{X}{13} = 45

5 - x + 9 = 4 x - 8 + 2

What are the solutions to the equation 6y^2-5y-6=0 ?
The solutions to the equation 6y^2-5y-6=0 are y= 3/2 ,y=-2/3
Find the zeros of 6y^2-5y-6=0
The zeros of 6y^2-5y-6=0 are y= 3/2 ,y=-2/3