What is (7x^2-x-1)-(x^2+3x+3) ?

The solution to (7x^2-x-1)-(x^2+3x+3) is 6x^2-4x-4

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simplify (7x^2-x-1)-(x^2+3x+3)

simplify

(7 x^{2} - x - 1) - (x^{2} + 3 x + 3)

6 x^{2} - 4 x - 4

Solution steps

(7 x^{2} - x - 1) - (x^{2} + 3 x + 3)

Apply rule:

(a) = a

(7 x^{2} - x - 1) = 7 x^{2} - x - 1

= 7 x^{2} - x - 1 - (x^{2} + 3 x + 3)

Apply the distributive law:

- (a + b) = - a - b

- (x^{2} + 3 x + 3) = - x^{2} - 3 x - 3

= 7 x^{2} - x - 1 - x^{2} - 3 x - 3

Group like terms

= 7 x^{2} - x^{2} - x - 3 x - 1 - 3

Add similar elements:

7 x^{2} - x^{2} = 6 x^{2}

= 6 x^{2} - x - 3 x - 1 - 3

Add similar elements:

- x - 3 x = - 4 x

= 6 x^{2} - 4 x - 1 - 3

Subtract the numbers:

- 1 - 3 = - 4

= 6 x^{2} - 4 x - 4

(7 y - 3) (2 y - 1)

\frac{- 6 - - 24}{2}

[3 (2 y + 3 b) + 7] [7 (2 y + 3 b) - 7]

\frac{7}{3 + 2}

\frac{7}{12} + \frac{5}{9}

What is (7x^2-x-1)-(x^2+3x+3) ?
The solution to (7x^2-x-1)-(x^2+3x+3) is 6x^2-4x-4