What are the solutions to the equation 3x^2-41x=-110 ?

The solutions to the equation 3x^2-41x=-110 are x=10,x= 11/3

Find the zeros of 3x^2-41x=-110

The zeros of 3x^2-41x=-110 are x=10,x= 11/3

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3 x^{2} - 41 x = - 110

x = 10, x = \frac{11}{3}

Solution steps

3 x^{2} - 41 x = - 110

Move

110

to the left side

3 x^{2} - 41 x + 110 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 3 \cdot 110}{2 \cdot 3}

(- 41)^{2} - 4 \cdot 3 \cdot 110 = 19

x_{1, 2} = \frac{- ( - 41 ) \pm 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 19}{2 \cdot 3}, x_{2} = \frac{- ( - 41 ) - 19}{2 \cdot 3}

x = \frac{- ( - 41 ) + 19}{2 \cdot 3} : 10

x = \frac{- ( - 41 ) - 19}{2 \cdot 3} : \frac{11}{3}

The solutions to the quadratic equation are:

x = 10, x = \frac{11}{3}

- 3 x = - 12

- \frac{8}{7} = - \frac{5}{2} v - \frac{7}{3}

3 x^{2} - 5 + 1 = 0

0 < ∣ x ∣ < \frac{1}{2}

- 3 u = 477

What are the solutions to the equation 3x^2-41x=-110 ?
The solutions to the equation 3x^2-41x=-110 are x=10,x= 11/3
Find the zeros of 3x^2-41x=-110
The zeros of 3x^2-41x=-110 are x=10,x= 11/3