What is (8xy)/(4^{-1)x^2y^{-2}} ?

The solution to (8xy)/(4^{-1)x^2y^{-2}} is (32y^3)/x

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simplify (8xy)/(4^{-1)x^2y^{-2}}

simplify

\frac{8 x y}{4 ^{- 1} x ^{2} y ^{- 2}}

\frac{32 y ^{3}}{x}

Solution steps

\frac{8 x y}{4 ^{- 1} x ^{2} y ^{- 2}}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 2 x y}{4 ^{- 1} x ^{2} y ^{- 2}}

\frac{4}{4 ^{- 1}} = 4^{2}

= \frac{4 ^{2} \cdot 2 x y}{x ^{2} y ^{- 2}}

Simplify

\frac{y}{y ^{- 2}} : y^{3}

= \frac{4 ^{2} \cdot 2 x y ^{3}}{x ^{2}}

Simplify

\frac{x}{x ^{2}} : \frac{1}{x}

= \frac{4 ^{2} \cdot 2 y ^{3}}{x}

Simplify

4^{2} \cdot 2 y^{3} : 32 y^{3}

= \frac{32 y ^{3}}{x}

(2 x - 3) (x^{2} - 3 x + 5)

r - 1 + 2 r

- 3 \cdot (- \frac{2}{3})

- 4 x^{2} y (x^{2} + 7 x y - 6 y^{3})

(2 u - t)^{2}

What is (8xy)/(4^{-1)x^2y^{-2}} ?
The solution to (8xy)/(4^{-1)x^2y^{-2}} is (32y^3)/x