What are the solutions to the equation w^2+8w+15=0 ?

The solutions to the equation w^2+8w+15=0 are w=-3,w=-5

Find the zeros of w^2+8w+15=0

The zeros of w^2+8w+15=0 are w=-3,w=-5

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w^{2} + 8 w + 15 = 0

w = - 3, w = - 5

Solution steps

w^{2} + 8 w + 15 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

w_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 8 + 2}{2 \cdot 1}, w_{2} = \frac{- 8 - 2}{2 \cdot 1}

w = \frac{- 8 + 2}{2 \cdot 1} : - 3

w = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

w = - 3, w = - 5

\frac{2 ^{3}}{2 ^{- 4}}

45 \leq 5 w

e^{- 3 x}

\frac{3 + 2 i}{i}

(50)^{2}

What are the solutions to the equation w^2+8w+15=0 ?
The solutions to the equation w^2+8w+15=0 are w=-3,w=-5
Find the zeros of w^2+8w+15=0
The zeros of w^2+8w+15=0 are w=-3,w=-5