What is expand 4n(5n^2-7n-3) ?

The solution to expand 4n(5n^2-7n-3) is 20n^3-28n^2-12n

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expand 4n(5n^2-7n-3)

expand

4 n (5 n^{2} - 7 n - 3)

20 n^{3} - 28 n^{2} - 12 n

Solution steps

4 n (5 n^{2} - 7 n - 3)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

4 n (5 n^{2} - 7 n - 3) = 4 n \cdot 5 n^{2} + 4 n (- 7 n) + 4 n (- 3)

= 4 n \cdot 5 n^{2} + 4 n (- 7 n) + 4 n (- 3)

Simplify

4 n \cdot 5 n^{2} + 4 n (- 7 n) + 4 n (- 3) : 20 n^{3} - 28 n^{2} - 12 n

= 20 n^{3} - 28 n^{2} - 12 n

(- 19 x^{2} - 4 x - 7) + (4 x^{2} + 25 x - 5)

\frac{12 a}{6 a}

- 5 + - 2 + i

(3 s + 5 p)^{3}

2 (x + 6) - 5 + 3 x

What is expand 4n(5n^2-7n-3) ?
The solution to expand 4n(5n^2-7n-3) is 20n^3-28n^2-12n