What is factor 3x^3+2x^2-19x+6 ?

The solution to factor 3x^3+2x^2-19x+6 is (3x-1)(x-2)(x+3)

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factor 3x^3+2x^2-19x+6

factor

3 x^{3} + 2 x^{2} - 19 x + 6

(3 x - 1) (x - 2) (x + 3)

Solution steps

3 x^{3} + 2 x^{2} - 19 x + 6

Use the rational root theorem

= (3 x - 1) \frac{3 x ^{3} + 2 x ^{2} - 19 x + 6}{3 x - 1}

\frac{3 x ^{3} + 2 x ^{2} - 19 x + 6}{3 x - 1} = x^{2} + x - 6

= (3 x - 1) (x^{2} + x - 6)

Factor

x^{2} + x - 6 : (x - 2) (x + 3)

= (3 x - 1) (x - 2) (x + 3)

x^{2} + 6 x + 9 = 0

3 (\frac{5}{6})^{2} - 5 (\frac{5}{6}) + 6

5 x^{2} - 40 x + 75

5 - 3 x \leq - 2

\frac{5 x ^{2} y + 5 x y ^{2}}{x + y}

What is factor 3x^3+2x^2-19x+6 ?
The solution to factor 3x^3+2x^2-19x+6 is (3x-1)(x-2)(x+3)