What is [(x^7y^{-7})^{-1}]^{-1} ?

The solution to [(x^7y^{-7})^{-1}]^{-1} is (x^7)/(y^7)

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simplify [(x^7y^{-7})^{-1}]^{-1}

simplify

[(x^{7} y^{- 7})^{- 1}]^{- 1}

\frac{x ^{7}}{y ^{7}}

Solution steps

((x^{7} y^{- 7})^{- 1})^{- 1}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (x^{7} y^{- 7})^{- 1 \cdot (- 1)}

- 1 \cdot (- 1) = 1

= (x^{7} y^{- 7})^{1}

Apply exponent rule:

a^{1} = a

= x^{7} y^{- 7}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 7} = \frac{1}{y ^{7}}

= \frac{1}{y ^{7}} x^{7}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot x ^{7}}{y ^{7}}

Multiply:

1 \cdot x^{7} = x^{7}

= \frac{x ^{7}}{y ^{7}}

(7 z^{3} - x y)^{4} - 9

(2 x + \frac{1}{2})^{2}

\frac{( x ^{6} - 1 )}{( x - 1 )}

\frac{12}{99}

85 + 115

What is [(x^7y^{-7})^{-1}]^{-1} ?
The solution to [(x^7y^{-7})^{-1}]^{-1} is (x^7)/(y^7)