What is (5x^{-3}y^0)^{-1} ?

The solution to (5x^{-3}y^0)^{-1} is (x^3)/5

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simplify (5x^{-3}y^0)^{-1}

simplify

(5 x^{- 3} y^{0})^{- 1}

\frac{x ^{3}}{5}

Solution steps

(5 x^{- 3} y^{0})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(5 x^{- 3} y^{0})^{- 1} = \frac{1}{5 x ^{- 3} y ^{0}}

= \frac{1}{5 x ^{- 3} y ^{0}}

Apply rule

a^{0} = 1, a \neq = 0

y^{0} = 1

= \frac{1}{5 \cdot 1 \cdot x ^{- 3}}

Multiply the numbers:

5 \cdot 1 = 5

= \frac{1}{5 x ^{- 3}}

Multiply

5 x^{- 3} : \frac{5}{x ^{3}}

= \frac{1}{\frac{5}{x ^{3}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{3}}{5}

\frac{25}{80}

(- 1)^{12}

\frac{225}{4}

3 (4 x + 5)

54 - 128 x^{3}