What is factor s^4+4s^3-7s^2-22s+24 ?

The solution to factor s^4+4s^3-7s^2-22s+24 is (s-1)(s-2)(s+3)(s+4)

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factor s^4+4s^3-7s^2-22s+24

factor

s^{4} + 4 s^{3} - 7 s^{2} - 22 s + 24

(s - 1) (s - 2) (s + 3) (s + 4)

Solution steps

s^{4} + 4 s^{3} - 7 s^{2} - 22 s + 24

Use the rational root theorem

= (s - 1) \frac{s ^{4} + 4 s ^{3} - 7 s ^{2} - 22 s + 24}{s - 1}

\frac{s ^{4} + 4 s ^{3} - 7 s ^{2} - 22 s + 24}{s - 1} = s^{3} + 5 s^{2} - 2 s - 24

= (s - 1) (s^{3} + 5 s^{2} - 2 s - 24)

Factor

s^{3} + 5 s^{2} - 2 s - 24 : (s - 2) (s + 3) (s + 4)

= (s - 1) (s - 2) (s + 3) (s + 4)

5 x - 7 + 3 x + 10

(\frac{2}{5})^{6}

16 c - 24

\frac{100}{18}

(x + 9)^{2} - (x - 9)^{2}

What is factor s^4+4s^3-7s^2-22s+24 ?
The solution to factor s^4+4s^3-7s^2-22s+24 is (s-1)(s-2)(s+3)(s+4)