What are the solutions to the equation 9x^2+18x=-11 ?

The solutions to the equation 9x^2+18x=-11 are x=-1+i(sqrt(2))/3 ,x=-1-i(sqrt(2))/3

Find the zeros of 9x^2+18x=-11

The zeros of 9x^2+18x=-11 are x=-1+i(sqrt(2))/3 ,x=-1-i(sqrt(2))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 18 x = - 11

x = - 1 + i \frac{2}{3}, x = - 1 - i \frac{2}{3}

Solution steps

9 x^{2} + 18 x = - 11

Move

11

to the left side

9 x^{2} + 18 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 11}{2 \cdot 9}

Simplify

1 8^{2} - 4 \cdot 9 \cdot 11 : 62 i

x_{1, 2} = \frac{- 18 \pm 6 2 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 6 2 i}{2 \cdot 9}, x_{2} = \frac{- 18 - 6 2 i}{2 \cdot 9}

x = \frac{- 18 + 6 2 i}{2 \cdot 9} : - 1 + i \frac{2}{3}

x = \frac{- 18 - 6 2 i}{2 \cdot 9} : - 1 - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{2}{3}, x = - 1 - i \frac{2}{3}

- 7 x - 1 > - 6 x + 12

\frac{n + 3}{4} - \frac{n - 2}{5} = \frac{n + 1}{10} - 1

(y^{6})^{\frac{2}{3}}

∣ 6 x - 5 ∣ = 0

- 5 \leq x

What are the solutions to the equation 9x^2+18x=-11 ?
The solutions to the equation 9x^2+18x=-11 are x=-1+i(sqrt(2))/3 ,x=-1-i(sqrt(2))/3
Find the zeros of 9x^2+18x=-11
The zeros of 9x^2+18x=-11 are x=-1+i(sqrt(2))/3 ,x=-1-i(sqrt(2))/3