What is (x^2-1)/(1-x) ?

The solution to (x^2-1)/(1-x) is -x-1

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simplify (x^2-1)/(1-x)

simplify

\frac{x ^{2} - 1}{1 - x}

- x - 1

Solution steps

\frac{x ^{2} - 1}{1 - x}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x + 1 ) ( x - 1 )}{1 - x}

1 - x = - (x - 1)

= \frac{( x + 1 ) ( x - 1 )}{- ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x + 1}{- 1}

Apply the fraction rule:

\frac{a}{- 1} = - a

= - (x + 1)

Apply the distributive law:

- (a + b) = - a - b

- (x + 1) = - x - 1

= - x - 1

6^{4} \cdot 6^{6}

\frac{6 n ^{2}}{( 3 n ) ^{5}}

a b^{2} (- a + b - c)

\frac{3 c}{c ^{- 1}}

6 \frac{5}{6}