What is (a^2+2ab+b^2)/(3a+3b) ?

The solution to (a^2+2ab+b^2)/(3a+3b) is (a+b)/3

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simplify (a^2+2ab+b^2)/(3a+3b)

simplify

\frac{a ^{2} + 2 ab + b ^{2}}{3 a + 3 b}

\frac{a + b}{3}

Solution steps

\frac{a ^{2} + 2 ab + b ^{2}}{3 a + 3 b}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

a^{2} + 2 ab + b^{2} = (a + b)^{2}

= \frac{( a + b ) ^{2}}{3 a + 3 b}

Factor out common term

3

= \frac{( a + b ) ^{2}}{3 ( a + b )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(a + b)^{2} = (a + b) (a + b)

= \frac{( a + b ) ( a + b )}{3 ( a + b )}

Cancel the common factor:

a + b

= \frac{a + b}{3}

- (2 x - 4.8 y) + 2.4

- \frac{1}{4} \cdot (- 2)

1 \div \frac{1}{8}

3 x^{3} + 192

What is (a^2+2ab+b^2)/(3a+3b) ?
The solution to (a^2+2ab+b^2)/(3a+3b) is (a+b)/3